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Please Solve RD Sharma Class 12 Chapter 4 Algebra of Matrices Exercise Very Short Asnwer Question 3 Maths Textbook Solution.

Answers (1)

Answer: AB=\begin{bmatrix} -7\\+2 \end{bmatrix}=\begin{bmatrix} -7\\2 \end{bmatrix}

Hint: Here, we use the basic multiplication rule, rule is one’s column and second’s row should be match, then multiplication is possible.

Given: A=\begin{bmatrix} 4 & 3\\ 1 & 2 \end{bmatrix},B=\begin{bmatrix} -4\\3 \end{bmatrix}

Solution:

Here A has 2 number of column and B has 2 number of row

AB = \begin{bmatrix} 4 &3 \\ 1& 2 \end{bmatrix}\begin{bmatrix} -4\\3 \end{bmatrix}=\begin{bmatrix} -16+9 \\ -4+6 \end{bmatrix}=\begin{bmatrix} -7\\+2 \end{bmatrix}

AB=\begin{bmatrix} -7\\2 \end{bmatrix}

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