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Please Solve RD Sharma Class 12 Chapter Algebra of Matrices Exercise 4.2 Question 11 Maths Textbook Solution.

Answers (1)

Answer:A = \begin{bmatrix} 8 & -3& 5\\ -2 & -3 & -6 \end{bmatrix}

Hint: Transposing the matrix from LHS to RHS

Given: \begin{bmatrix} 1 & 2 &-1 \\ 0 & 4 & 9 \end{bmatrix} + A =\begin{bmatrix} 9 &-1 &4 \\ -2& 1 &3 \end{bmatrix}

Here, we have to compute A.

Solution:

\begin{bmatrix} 1 & 2 &-1 \\ 0 & 4 & 9 \end{bmatrix} + A =\begin{bmatrix} 9 &-1 &4 \\ -2& 1 &3 \end{bmatrix} 

A =\begin{bmatrix} 9 &-1 &4 \\ -2& 1 &3 \end{bmatrix}-\begin{bmatrix} 1 & 2 &-1 \\ 0 & 4 & 9 \end{bmatrix}

A =\begin{bmatrix} 9-1 &-1-2 &4 +1\\ -2-0& 1-4 &3 -9 \end{bmatrix}

A = \begin{bmatrix} 8 & -3& 5\\ -2 & -3 & -6 \end{bmatrix}                                                                                                                                                                                                                                                                                    

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