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Please Solve RD Sharma Class 12 Chapter Algebra of Matrices Exercise 4.1 Question 6 Subquestion (iii) Maths Textbook Solution.

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Answer: A= \begin{bmatrix} 2 &2 &2 &2\\ 4 &4 &4 &4 \\ 6 &6 &6 &6 \end{bmatrix}

Given: a_{ij}= \left (2i \right )
            Here we have to construct 3\times 4  matrix according to \left (2i \right )

Hint: Substitute the required value according \left (2i \right )  

Solution: Here a_{ij}= \left (2i \right )

                  Let A= \left [ a_{ij} \right ]_{3\times 4}

So, A= \begin{bmatrix} a_{11} &a_{12} &a_{13} & a_{14}\\ a_{21} &a_{22} & a_{23} & a_{24}\\ a_{31} & a_{32} & a_{33} &a_{34} \end{bmatrix}_{3\times 4}

\! \! \! \! \! \! \! \! \! a_{11}= 2\times 1= 2\\a_{12}= 2\times 1= 2\\a_{13}= 2\times 1=2\\a_{14}= 2\times 1= 2             \! \! \! \! \! \! \! \! \! a_{21}= 2\times 2= 4\\a_{22}= 2\times 2= 4\\a_{23}= 2\times 2=4\\a_{24}= 2\times 2= 4            \! \! \! \! \! \! \! \! \! a_{31}= 2\times 3= 6\\a_{32}= 2\times 3= 6\\a_{33}= 2\times 3=6\\a_{34}= 2\times 3= 6

Substituting these values in Matrix A , we get

A= \begin{bmatrix} 2 &2 &2 &2\\ 4 &4 &4 &4 \\ 6 &6 &6 &6 \end{bmatrix}

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