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Please Solve RD Sharma Class 12 Chapter 4 Algebra of Matrices Exercise Very Short Asnwer Question 18 Maths Textbook Solution.

Answers (1)

Answer: A=\begin{bmatrix} {1} & {-9}\\ {-2}& {4} \end{bmatrix}

Hint: Here we use the basic algebra of matrix

 

Given:

A+\begin{bmatrix} 23 & -14 \end{bmatrix}=\begin{bmatrix} 3 &-6 &-38 \end{bmatrix}

Solution:

Let A=\begin{bmatrix} a_{11} & a_{12}\\ a_{21}& a_{22} \end{bmatrix}

So,

\begin{bmatrix} a_{11} &a_{12} &a_{21} &a_{22} \end{bmatrix}+\begin{bmatrix} 23 & -14 \end{bmatrix}=\begin{bmatrix} 3 & -6 & 38 \end{bmatrix}a_{11}+2=3=1a_{12}+3=-6=-9a_{21}+\left ( -1 \right )

So, A=\begin{bmatrix} {1} & {-9}\\ {-2}& {4} \end{bmatrix}

 

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