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  • Please Solve RD Sharma Class 12 Chapter Algebra of Matrices Exercise 4.2 Question 18 Subquestion (ii) Maths Textbook Solution.

Please Solve RD Sharma Class 12 Chapter Algebra of Matrices Exercise 4.2 Question 18 Subquestion (ii) Maths Textbook Solution.

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Answer: X = \begin{bmatrix} -2 &\frac{-10}{3} \\ \\ 12 &\frac{14}{3} \\ \\ \frac{-31}{3} & \frac{-7}{3} \end{bmatrix}

Hint: Take the variable 3X into RHS and 5B into LHS. Then, solve.

Given:A =\begin{bmatrix} 8 & 0\\ 4&-2 \\ 3&6 \end{bmatrix} , B =\begin{bmatrix} 2 &-2 \\ 4& 2\\ -5& 1 \end{bmatrix} , 2A + 3X = 5B

Here, we have to compute X.

Solution:

2A + 3X = 5B

2\begin{bmatrix} 8 & 0\\ 4& -2\\ 3&6 \end{bmatrix} + 3X = 5\begin{bmatrix} 2&-2 \\ 4 &2 \\ -5 &1 \end{bmatrix}

\begin{bmatrix} 16 & 0\\ 8& -4\\ 6&12 \end{bmatrix} + 3X = \begin{bmatrix} 10&-10 \\ 20 &10 \\ -25 &5 \end{bmatrix}

3X = \begin{bmatrix} 10&-10 \\ 20 &10 \\ -25 &5 \end{bmatrix}-\begin{bmatrix} 16 & 0\\ 8& -4\\ 6&12 \end{bmatrix}

3X = \begin{bmatrix} -6 &-10 \\ 12 &14 \\ -31 &-7 \end{bmatrix}

X = \frac{1}{3}\begin{bmatrix} -6 &-10 \\ 12 &14 \\ -31 &-7 \end{bmatrix}

X = \begin{bmatrix} -2 &\frac{-10}{3} \\ \\ 12 &\frac{14}{3} \\ \\ \frac{-31}{3} & \frac{-7}{3} \end{bmatrix}

 

 

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