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Please Solve RD Sharma Class 12 Chapter 4 Algebra of Matrices Exercise Very Short Asnwer Question 10 Maths Textbook Solution.

Answers (1)

Answer: y=\left ( -2 \right )\: and\: x=0

Hint: Here we use the concept of identity matrix

Given: \begin{bmatrix} 1 & 0\\ y & 5 \end{bmatrix}+2\begin{bmatrix} x &0 \\ 1& -2 \end{bmatrix}=I

Solution:

\begin{aligned} &{\left[\begin{array}{ll} 1 & 0 \\ y & 5 \end{array}\right]+2\left[\begin{array}{cc} x & 0 \\ 1 & -2 \end{array}\right]=\left[\begin{array}{ll} 1 & 0 \\ 0 & 1 \end{array}\right]} \\ &{\left[\begin{array}{ll} 1 & 0 \\ y & 5 \end{array}\right]+\left[\begin{array}{cc} 2 x & 0 \\ 2 & -4 \end{array}\right]=\left[\begin{array}{ll} 1 & 0 \\ 0 & 1 \end{array}\right]} \\ &{\left[\begin{array}{ll} 2 x+1 & 0 \\ y+2 & 1 \end{array}\right]=\left[\begin{array}{ll} 1 & 0 \\ 0 & 1 \end{array}\right]} \\ &\text { So } 2 x+1=1 \\ &2 x=0 \\ &\begin{array}{l} x=0 \\ y+2=0 \end{array} \\ &y=(-2) \end{aligned}

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