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Please Solve RD Sharma Class 12 Chapter Algebra of Matrices Exercise 4.1 Question 6 Suquestion (i) Maths Textbook Solution.

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Answer:   A= \begin{bmatrix} 2 &3 &4 &5 \\ 3 &4 &5 &6 \\ 4 &5 &6 &7 \end{bmatrix}

Given: a_{ij}= \left ( i+j \right )
             Here we have to construct 3\times 4  matrix according to \left ( i+j \right )

Hint: Find the sum of i and j  for each element.

Solution:  Here a_{ij}= \left ( i+j \right )

   Let A= \left [ a_{ij} \right ]_{3\times 4}

So, A= \begin{bmatrix} a_{11} &a_{12} &a_{13} & a_{14}\\ a_{21} &a_{22} & a_{23} & a_{24}\\ a_{31} & a_{32} & a_{33} &a_{34} \end{bmatrix}_{3\times 4}         

\! \! \! \! \! \! \! \! \! a_{11}= 1+1= 2\\a_{12}= 1+2= 3\\a_{13}= 1+4=4\\a_{14}= 1+4= 5           \! \! \! \! \! \! \! \! \! a_{21}= 2+1= 3\\a_{22}= 2+2= 4\\a_{23}= 2+3=5\\a_{24}= 2+4= 6            \! \! \! \! \! \! \! \! \! a_{31}= 3+1= 4\\a_{32}= 3+2= 5\\a_{33}= 3+3=6\\a_{34}= 3+4= 7

Substituting these values in Matrix A , we get

A= \begin{bmatrix} 2 &3 &4 &5 \\ 3 &4 &5 &6 \\ 4 &5 &6 &7 \end{bmatrix}

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