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Need solution for RD Sharma maths class 12 chapter Algebra of matrices exercise 4.3 question 37math

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Answer:  Hence provedf(A)=0

Hint: I is an identity matrix.

Matrix multiplication is only possible, when the number of columns of first matrix is equal to the number of rows of second matrix.

Given: A=\left[\begin{array}{ll}1 & 2 \\ 2 & 1\end{array}\right]and f(x)=x^{2}-2 x-3

To show that f(A)=0

Substitute x=A in f(x) we get

f(A)=A^{2}-2 A-3 I---i\\\\ f(A)=\left[\begin{array}{ll}1 & 2 \\ 2 & 1\end{array}\right]\left[\begin{array}{ll}1 & 2 \\ 2 & 1\end{array}\right]-2\left[\begin{array}{ll}1 & 2 \\ 2 & 1\end{array}\right]-3\left[\begin{array}{ll}1 & 0 \\ 0 & 1\end{array}\right]\\\\ =\left[\begin{array}{ll}1+4 & 2+2 \\ 2+2 & 4+1\end{array}\right]-\left[\begin{array}{ll}2 & 4 \\ 4 & 2\end{array}\right]-\left[\begin{array}{ll}3 & 0 \\ 0 & 3\end{array}\right] =\left[\begin{array}{ll}5 & 4 \\ 4 & 5\end{array}\right]-\left[\begin{array}{ll}2 & 4 \\ 4 & 2\end{array}\right]-\left[\begin{array}{ll}3 & 0 \\ 0 & 3\end{array}\right]\\\\ =\left[\begin{array}{lll}5-2-3 & 4-4-0 \\ 4-4-0 & 5-2-3\end{array}\right]\\\\ =\left[\begin{array}{ll}0 & 0 \\ 0 & 0\end{array}\right]\\\\ =0\\\\

So, f (A) = 0

Hence, proved

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