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Please Solve RD Sharma Class 12 Chapter 4 Algebra of Matrices Exercise Very Short Asnwer Question 53 Maths Textbook Solution.

Answers (1)

Answer: b=2

Hint: Here we use basic concept of algebra

Given: \begin{bmatrix} a-b & 2a+c\\ 2a-b &3c+d \end{bmatrix}=\begin{bmatrix} -1 &5 \\ 0 & 13 \end{bmatrix}

Solution:

Here both sides has 2\times2 matrix

So,we can write

a-b=-1    ....1i)

2a-b=0     .....(2)

\rightarrowLet's multiply (-2) with eqn (1)

-2a+2b=+2

\! \! \! \! \! \! \! \! \! \! 2a-b=0\\ \overline{0+b=2}

b=2

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