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Please Solve RD Sharma Class 12 Chapter Algebra of Matrices Exercise 4.2 Question 2 Subquestion (iv) Maths Textbook Solution.

Answers (1)

Answer: \begin{bmatrix} -2 &21 \\ 22 &8 \end{bmatrix}

Hint: Multiply the A, B, and C with 3, 2, and 3 respectively. Then, solve 3A – 2B + 3C.

Given: A= \begin{bmatrix} 2 &4 \\ 3 &2 \end{bmatrix} , B= \begin{bmatrix} 1 &3 \\ -2 &5 \end{bmatrix}  and C= \begin{bmatrix}-2 &5 \\ 3 &4 \end{bmatrix}

Here, we have to compute 3A - 2B + 3C.

Solution:
3A-2B+3C=3 \begin{bmatrix} 2 &4 \\ 3 &2 \end{bmatrix}-2 \begin{bmatrix} 1 &3 \\ -2 &5 \end{bmatrix}+3\begin{bmatrix} -2 & 5\\ 3 & 4 \end{bmatrix}

                              = \begin{bmatrix} 6 & 12\\ 9 &6 \end{bmatrix}- \begin{bmatrix} 2 &6 \\ -4 &10 \end{bmatrix}+\begin{bmatrix} -6 & 15\\ 9& 12 \end{bmatrix}

                                = \begin{bmatrix} 6-2-6 & 12-6+15\\ 9+4+9 &6-10+12 \end{bmatrix}

                                = \begin{bmatrix} -2 &21 \\ 22 &8 \end{bmatrix}
 

 

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