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Explain Solution R.D. Sharma Class 12 Chapter 22 Algebra of Vectors  Exercise Very Short Answer Type Question 38 Maths Textbook Solution.

Answers (1)

Answer: \frac{1}{\sqrt{14}},\frac{2}{\sqrt{14}},\frac{3}{14}

Hint: You must know the rules of vector functions

Given: \hat{i}+2\hat{j}+3\hat{k}, find direction cosines

Solution: Let \hat{i}+2\hat{j}+3\hat{k}

Hence direction cosines are,

\begin{aligned} &\frac{1}{\sqrt{(1)^{2}+(2)^{2}+(3)^{2}}}, \frac{2}{\sqrt{(1)^{2}+(2)^{2}+(3)^{2}}}, \frac{3}{\sqrt{(1)^{2}+(2)^{2}+(3)^{2}}} \\ &=\frac{1}{\sqrt{1+4+9}}, \frac{2}{\sqrt{1+4+9}}, \frac{3}{\sqrt{1+4+9}} \\ &=\frac{1}{\sqrt{14}}, \frac{2}{\sqrt{14}}, \frac{3}{\sqrt{14}} \end{aligned}

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