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Explain Solution R.D.Sharma Class 12 Chapter 22 Algebra of Vectors  Exercise 22.2 Question 9 Maths Textbook Solution.

Answers (1)

Answer:

We need to prove that

Hint:

Use triangle law.

Given :

\vec{AD}+\vec{PB}+\vec{PD}=\vec{PC}

                                                \vec{AD}+\vec{PB}+\vec{PD}-\vec{PC}

Solution:

                 

In \Delta PDC,by triangle law

\vec{PD}+\vec{DC}=\vec{PC}

In \Delta PAB,by triangle law

\vec{PA}+\vec{PB}=\vec{AB}

\therefore ABCD is a parallelogram.

    

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