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  • Explain Solution R.D. Sharma Class 12 Chapter 22 Algebra of Vectors Exercise Very Short Answer Type Question 35 Maths Textbook Solution.

Explain Solution R.D. Sharma Class 12 Chapter 22 Algebra of Vectors  Exercise Very Short Answer Type Question 35 Maths Textbook Solution.

Answers (1)

Answer:    Both have the same magnitude.

Hint: You must know the rules of solving vectors

Given: Write two different vectors having same magnitude

Solution:

            Let  \begin{aligned} &\vec{a}=2 \hat{i}-\hat{j}+2 \hat{k} \\ &\vec{b}=-2 \hat{i}+\hat{j}-2 \hat{k} \end{aligned}

\begin{aligned} &|\vec{a}|=\sqrt{(2)^{2}+(-1)^{2}+(2)^{2}}=\sqrt{4+1+4}=\sqrt{9}=3 \\ &|\vec{b}|=\sqrt{(-2)^{2}+(1)^{2}+(-2)^{2}}=\sqrt{4+1+4}=\sqrt{9}=3 \end{aligned}

Hence, both vectors are having the same magnitude.

 

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