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Explain solution RD sharma class 12 chapter 22 algebra of vectors exercise 22.5, question 12 sub question 3

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The components of \vec{R} along x axis is a vector of magnitude 11 along the negative direction of x axis

The component of \vec{R} along y axis is a vector of magnitude 9 along the negative direction of Y axis

-11\hat{i},-9\hat{j}

Hint: position vector of point (x, y) is given by x\hat{i}+y\hat{j} where \hat{i} and \hat{j} are the unit vector in x and y direction

Given:R=(-11,-9)

Solution:

As we know, position vector of a point (x, y) is given by x\hat{i}+y\hat{j}

So

\vec{R}=-11\hat{i}+(-9)\hat{j}\\ \vec{R}=-11\hat{i}-9\hat{j}\\

The components of \vec{R} along x-axis is a vector of magnitude 11 along the negative direction of x axis

The component of \vec{R} along y-axis is a vector of magnitude 9 along the negative direction of Y axis

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