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Explain solution RD sharma class 12 chapter 22 algebra of vectors exercise 22.5, question 12 sub question 2

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The components of \vec{Q} along x axis is a vector of magnitude 5 along the negative direction of x axis

The component of \vec{Q} along y axis is a vector of magnitude 1 along the positive direction of Y axis

-5\hat{i},\hat{j}

Hint: position vector of point (x, y) is given by x\hat{i}+y\hat{j} where \hat{i} and \hat{j} are the unit vector in x and y direction

Given:Q=(-5,1)

Solution:

As we know, position vector of a point (x, y) is given by x\hat{i}+y\hat{j}

So

\vec{Q}=-5\hat{i}+1\hat{j}\\ \vec{Q}=-5\hat{i}+\hat{j}\\

The components of \vec{Q} along x axis is a vector of magnitude 5 along the negative direction of x axis

The component of \vec{Q} along y axis is a vector of magnitude 1 along the positive direction of Y axis

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