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  • Need Solution for R.D.Sharma Maths Class 12 Chapter 22 Algebra of Vectors Exercise very Short Answer type Question 52 Maths Textbook Solution.

Need Solution for R.D.Sharma Maths Class 12 Chapter 22 Algebra of Vectors  Exercise very Short Answer type Question 52 Maths Textbook Solution.

Answers (1)

Answer: \frac{7}{3}\vec{a}+\frac{4}{3}\vec{b}

Hint: You must know the rules of vector functions

Given: Write the position vector of the point which divides the join of points with position vectors 3\vec{a}-2\vec{b} &2\vec{a}+3\vec{b} in ratio 2:1

Solution: Let R be the point which divides the line joining point with vectors.

3\vec{a}-2\vec{b}&2\vec{a}+3\vec{b} in ratio 2:1

And

\overrightarrow{O A}=3 \vec{a}-2 \vec{b}

\overrightarrow{O B}=2 \vec{a}+3 \vec{b}

Here m: n=2: 1

Position vector of \overline{O R}is as follows

\overline{O R}=\frac{m \overline{O B}+n \overline{O A}}{m+n}

=\frac{2(2 \vec{a}+3 \vec{b})+1(3 \vec{a}-2 \vec{b})}{2+1}

=\frac{4 \vec{a}+6 \vec{b}+3 \vec{a}-2 \vec{b}}{3}

=\frac{7 \vec{a}+4 \vec{b}}{3}

=\frac{7}{3} \vec{a}+\frac{4}{3} \vec{b}

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