Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • School
  • Please Solve RD Sharma Class 12 Chapter 22 Algebra of Vectors Exercise 22.6 Question 2 Maths Textbook Solution.

Please Solve RD Sharma Class 12 Chapter 22 Algebra of Vectors Exercise 22.6 Question 2 Maths Textbook Solution.

Answers (1)

Answer:

The unit vector will be  \frac{3}{13} \hat{\imath}+\frac{4}{13} \hat{\jmath}-\frac{12}{13} \hat{k}

Hint:

Use vector magnitude formula.

Given:

3 \hat{\imath}+4 \hat{\jmath}-12 \hat{k}

Solution:

Let the unit vector in the direction of  \vec{A}=3 \hat{\imath}+4 \hat{\jmath}-12 \hat{k} \text { be } \vec{B}

So, any unit vector in the direction of   \vec{A}=3 \hat{\imath}+4 \hat{j}-12 \hat{k}   will be

 \vec{B}=\frac{\vec{A}}{|\vec{A}|}

So, the magnitude of the vector

|\vec{A}|=\sqrt{3^{2}+4^{2}+(-12)^{2}}
\begin{aligned} &|\vec{A}|=\sqrt{9+16+144}=\sqrt{169} \\ &|\vec{A}|=13 \end{aligned}

So, the unit vector

 \vec{B}=\frac{3 \hat{\dagger}+4 \hat{\jmath}-12 \hat{k}}{13}=\frac{3}{13} \hat{i}+\frac{4}{13} \hat{\jmath}-\frac{12}{13} \hat{k}

Posted by

infoexpert27

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads

Similar Questions

Trending Articles/News

anam-khan

PM Modi's Pariksha Pe Charcha 2025 to be held next month, registrations open till January 14
anam-khan

CBSE Board Exams 2025: Online portal for availing exemptions by CWSN students opens
anam-khan

Board Exams: States agree to equivalence; no question paper ‘jumbling’ from next year, says PARAKH CEO

Latest Question