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  • Explain Solution RD Sharma Class 12 Chapter Algebra of Vectors Exercise 22.6 Question 6 Maths.

Explain Solution RD Sharma Class 12 Chapter Algebra of Vectors Exercise 22.6 Question 6 Maths.

Answers (1)

Answer:

The position vector Q has co - ordinate \left ( 4,1,1 \right )

Hint:

Find the vector equation of Q.

Given:

P \vec{Q}=3 \hat{\imath}+2 \hat{\jmath}-\hat{k}  and the co - ordinates of P is \left ( 1,-1,2 \right )

Solution:

Let the position vector of point Q is \overrightarrow{a}

So, we need to find the value of  \overrightarrow{a}

P \vec{Q}=  Position vector of Q – Position vector of P

\begin{gathered} 3 \hat{\imath}+2 \hat{\jmath}-\hat{k}=\vec{a}-(\hat{\imath}-\hat{\jmath}+2 \hat{k}) \\ 3 \hat{\imath}+2 \hat{\jmath}-\hat{k}=\vec{a}-\hat{i}+\hat{j}-2 \hat{k} \\ \vec{a}=3 \hat{\imath}+2 \hat{\jmath}-\hat{k}+\hat{i}-\hat{j}+2 \hat{k} \\ \end{gathered}
 \vec{a}=4 \hat{\imath}+\hat{\jmath}+\hat{k}

So, the coordinates of position vector Q is \left ( 4,1,1 \right )

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