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  • Explain solution RD sharma class 12 chapter 22 algebra of vectors exercise 22 .5, question 12 sub question 4

Explain solution RD sharma class 12 chapter 22 algebra of vectors exercise 22.5, question 12 sub question 4

Answers (1)

The components of \vec{S} along x axis is a vector of magnitude 4 along the positive direction of x axis

The component of \vec{S} along y axis is a vector of magnitude 3 along the negative direction of Y axis

4\hat{i},-3\hat{j}

Hint: position vector of point (x, y) is given by x\hat{i}+y\hat{j} where \hat{i} and \hat{j} are the unit vector in x and y direction

Given:S=(-4,-3)

Solution:

As we know, position vector of a point (x, y) is given by x\hat{i}+y\hat{j}

So

\vec{S}=4\hat{i}+(-3)\hat{j}\\ \vec{S}=4\hat{i}-3\hat{j}\\

The components of \vec{S} along x-axis is a vector of magnitude 4 along the positive direction of x-axis

The component of \vec{S} along y-axis is a vector of magnitude 3 along the negative direction of Y-axis

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