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Provide Solution For  R .D. Sharma Maths Class 12 Chapter 22 Algebra of Vectors  Exercise Very Short Answer Type  Question 23 Maths Textbook Solution.

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Answer:\frac{-\hat{i}+2\hat{j}-\hat{k}}{\sqrt{6}}

Hint: You must know the rules of vector functions

Given: \vec{a}=\hat{i}+\hat{j}, \vec{b}=\hat{j}+\hat{k} \& \vec{c}=\hat{k}+\hat{i} find unit vector parallel to \vec{a}+\vec{b}-2\vec{c}

Solution: \vec{a}=\hat{i}+\hat{j}, \vec{b}=\hat{j}+\hat{k} \& \vec{c}=\hat{k}+\hat{i}

   Now,

\begin{aligned} &\vec{a}+\vec{b}-2 \vec{c}=\hat{i}+\hat{j}+\hat{j}+\hat{k}-2 \hat{k}-2 \hat{i} \\ &=-\hat{i}+2 \hat{j}-\hat{k} \end{aligned}

Unit vector parallel to,

\begin{aligned} &\vec{a}+\vec{b}-2 \vec{c}=\frac{-\hat{i}+2 \hat{j}-\hat{k}}{\sqrt{(-1)^{2}+(2)^{2}+(1)^{2}}} \\ &=\frac{-\hat{i}+2 \hat{j}-\hat{k}}{\sqrt{6}} \end{aligned}

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