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  • Explain Solution R.D. Sharma Class 12 Chapter 22 Algebra of Vectors Exercise Very Short Answer Type Question 37 Maths Textbook Solution.

Explain Solution R.D. Sharma Class 12 Chapter 22 Algebra of Vectors  Exercise Very Short Answer Type Question 37  Maths Textbook Solution.

Answers (1)

Answer:  \frac{8}{\sqrt{30}}\left ( 5\hat{i}-\hat{j}+2\hat{k} \right )

Hint: You must know the rules of vector functions

Given: Write a vector in direction of 5\hat{i}-\hat{j}+2\hat{k} having magnitude 8 units

Solution: Let \vec{a}= 5\hat{i}-\hat{j}+2\hat{k}

\begin{aligned} &|\vec{a}|=\sqrt{(5)^{2}+(-1)^{2}+(2)^{2}}\\ &=\sqrt{25+1+4}\\ &=\sqrt{30} \end{aligned}

Position vector in the direction of vector is,

\begin{aligned} &=8 \times \frac{\vec{a}}{|\vec{a}|} \\ &=\frac{8}{\sqrt{30}}(5 \hat{i}-\hat{j}+2 \hat{k}) \end{aligned}

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