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Need Solution for R.D.Sharma Maths Class 12 Chapter 22 Algebra of Vectors  Exercise very Short Answer type Question 43 Maths Textbook Solution.

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Answer: \frac{3}{7}\hat{i}-\frac{2}{7}\hat{j}+\frac{6}{7}\hat{k}

Hint: You must know the rules of vector functions

Given: Find unit vector in direction of \vec{a}=3\hat{i}-2\hat{j}+6\hat{k}

Solution: \vec{a}=3\hat{i}-2\hat{j}+6\hat{k}

Unit vector \begin{aligned} &\frac{\vec{a}}{\mid \vec{a}\mid }=\frac{3 \hat{i}-2 \hat{j}+6 \hat{k}}{\sqrt{(3)^{2}+(-2)^{2}+(6)^{2}}} \\ \end{aligned}

\begin{aligned} &=\frac{3 \hat{\imath}-2 \hat{\jmath}+6 \hat{k}}{\sqrt{9+4+36}} \\ &=\frac{3 \hat{\imath}-2 \hat{\jmath}+6 \hat{k}}{\sqrt{49}} \\ &=\frac{3 \hat{\imath}-2 \hat{\jmath}+6 \hat{k}}{7} \\ &=\frac{3}{7} \hat{\imath}-\frac{2}{7} \hat{\jmath}+\frac{6}{7} \hat{k} \end{aligned}

 

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