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Explain Solution R.D.Sharma Class 12 Chapter 23 Scalar or Dot Products Exercise 23.1 Question 42 Maths Textbook Solution.

Answers (1)

Answer: Proved

Hint: You must know the rules of solving vectors.

Given: If \vec{a},\vec{b},\vec{c} are three non-coplanar vectors, such that \vec{a}.\vec{a}=\vec{d}.\vec{b}=\vec{d}.\vec{c}=0 then show that \vec{d} is the null vector.

Solution:

Given that \vec{a}\cdot \vec{a}=0

So, either \vec{a}=0or \vec{d}\perp\vec{a}

Similarly, \vec{d}\cdot \vec{b}=0

So, \vec{d}=0 or \vec{d}\perp\vec{b}

Also, \vec{d}\cdot \vec{c}=0

So, \vec{d}=0 or \vec{d}\perp \vec{c}

But \vec{d} cannot be perpendicular to \vec{a},\vec{b},\vec{c} as\vec{a},\vec{b},\vec{c} are non-coplanar

So, \vec{d}=0,\vec{d} is null vector.

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