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  • Explain solution RD Sharma class 12 Chapter 23 Scalar or Dot Products Exercise Very Short Answer question 7

Explain solution RD Sharma class 12 Chapter 23 Scalar or Dot Products Exercise Very Short Answer question 7

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ANSWER:  \overrightarrow{|a|}= |\overrightarrow{b}|

GIVEN:  (\vec{a}+\vec{b}) \cdot(\vec{a}-\vec{b})=0

HINTS:Use the identity of  \left(a^{2}-b^{2}\right)

SOLUTION:

\begin{aligned} &(\vec{a}+\vec{b}) \cdot(\vec{a}-\vec{b})=0 \\ & \end{aligned}

\Rightarrow|\vec{a}|^{2}-|\vec{b}|^{2}=0 \qquad \qquad \qquad\left[\because(a+b)(a-b)=a^{2}-b^{2}\right] \\

\Rightarrow|\vec{a}|^{2}=|\vec{b}|^{2} \\

\Rightarrow|\vec{a}|=|\vec{b}|

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