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  • Please Solve RD Sharma Class 12 Chapter 23 Scalar or Dot Product Exercise Very Short Answer Question 1 Maths Textbook Solution.

Please Solve RD Sharma Class 12 Chapter 23 Scalar or Dot Product Exercise Very Short Answer Question 1 Maths Textbook Solution.

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ANSWER:  \frac{\pi}{3}

GIVEN:  |\vec{a}|=2 \quad \&|\vec{b}|=\sqrt{3} \quad \& \vec{a} \cdot \vec{b}=\sqrt{3}

HINTS:Use the formula of cos θ

SOLUTION:Let θ be the angle between vectors  \vec{a} \& \vec{b} then,

\begin{aligned} &\cos \theta=\frac{\vec{a} \cdot \vec{b}}{|\vec{a}| \vec{b} \|} \\ & \end{aligned}

\Rightarrow \cos \theta=\frac{\sqrt{3}}{2 \sqrt{3}} \qquad\qquad\qquad[\because \vec{a} \cdot \vec{b}=\sqrt{3},|\vec{a}|=2 \&|\vec{b}|=\sqrt{3}] \\

\Rightarrow \cos \theta=\frac{1}{2} \Rightarrow \theta=\frac{\pi}{3} \qquad\qquad\qquad\left[\because \cos \frac{\pi}{3}=\frac{1}{2}\right]

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