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  • Need Solution for R.D. Sharma Maths Class 12 Chapter 23 Scalar or Dot Products Exercise 23.1 Question 32 Sub Question 3 Maths Textbook Solution.

Need Solution for R.D. Sharma Maths Class 12 Chapter 23 Scalar or Dot  Products  Exercise 23.1 Question 32 Sub Question 3 Maths Textbook Solution.

Answers (1)

Answer:  \sqrt{5}

Hint:  You must know the rules of solving vectors.

Given:   Find \mid \vec{a}-\vec{b} if \mid \vec{a}\mid =2 , \mid \vec{b}\mid =3   & \vec{a}.\vec{b}=4

Solution:

\mid \vec{a}\mid =2 , \mid \vec{b}\mid =3   & \vec{a}.\vec{b}=4

We know,

\begin{aligned} &|\vec{a}-\vec{b}|^{2}=|\vec{a}|^{2}+|\vec{b}|^{2}-2(\vec{a} \cdot \vec{b}) \\ &|\vec{a}-\vec{b}|^{2}=(2)^{2}+(3)^{2}-2(4) \\ &|\vec{a}-\vec{b}|^{2}=4+9-8 \\ \end{aligned}

\begin{aligned} &\qquad|\vec{a}-\vec{b}|^{2}=5 \\ \end{aligned}

\begin{aligned} &\therefore|\vec{a}-\vec{b}|=\sqrt{5} \end{aligned}

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