Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • School
  • Need solution for RD Sharma Maths Class 12 Chapter 23 Scalar or Dot Products Excercise Very Short Answer Question 24

Need solution for RD Sharma Maths Class 12 Chapter 23 Scalar or Dot Products Excercise Very Short Answer Question 24

Answers (1)

best_answer

Answer :-  \sqrt{2}

Hint :- Use the identity  \left ( a+b\right )^{2}

Given :-   |\vec{a}|=|\vec{b}|=1 \& \vec{a} \cdot \vec{b}=0

Solution :-  |\vec{a}+\vec{b}|^{2}=|\vec{a}|^{2}+|\vec{b}|^{2}+2 \vec{a} \cdot \vec{b} \qquad\qquad\left[\because(a+b)^{2}=a^{2}+b^{2}+2 \mathrm{ab}\right]

\begin{aligned} &\Rightarrow|\vec{a}+\vec{b}|^{2}=(1)^{2}+(1)^{2}+2 * 0 \qquad[\because|\vec{a}|=|\vec{b}|=1 \& \vec{a} \cdot \vec{b}=0] \\ & \end{aligned}

\Rightarrow|\vec{a}+\vec{b}|^{2}=2 \\

\Rightarrow|\vec{a}+\vec{b}|=\sqrt{2}

 

Posted by

infoexpert27

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads

Similar Questions

Trending Articles/News

anam-khan

CBSE reduces re-evaluation fee to Rs 100, to refund if marks change
anam-khan

CBSE defends OSM evaluation process, says re-evaluation option remains open
anam-khan

‘Feeling Devastated’: CBSE 12th students allege low marks due to on-screen marking; call for manual evaluation

Latest Question