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Explain solution RD Sharma class 12 chapter Scaler and Dot Product exercise 23.2 question 4 maths

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Answer: 2\left(|a|^{2}+|b|^{2}\right)

Hint: Let diagonal vector (\vec{a}+\vec{b}) \text { and }(\vec{a}-\vec{b})

Given: P.T by vector method that sum of square of diagonal of parallelogram

Equal to sum of square of sides

Solution:  Let adjacent side of parallelogram \vec{a} \text { and } \vec{b}

Then diagonal vector will be (\vec{a}+\vec{b}) \text { and }(\vec{a}-\vec{b})

Sum of squares of diagonal

(\vec{a}+\vec{b})^{2}+(\vec{a}-\vec{b})^{2}=2\left(|a|^{2}+|b|^{2}\right)

Sum of squares of side

2\left(|a|^{2}+|b|^{2}\right)

Hence proved

 

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