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  • Explain solution RD sharma class 12 chapter 23 scalar or dot product exercise Fill in the blanks question 15

Explain solution RD sharma class 12 chapter 23 scalar or dot product exercise Fill in the blanks question 15

Answers (1)

4

Hint:

               \left |a \right |=?

Given:

If a,b non-zero vector of same magnitude. Such that angle between \vec{a} and \vec{b} are \frac{2\pi}{3} and a.b=-8 then  \left | a \right |

Solution:

Let     

\left | a \right |=m\\ \vec{a}.\vec{b}=-8\\ \left |\vec{a} \right |.\left |\vec{b} \right |.\cos \theta =-8\\

m^{2}\left ( -\frac{1}{2} \right ) =-8\\,since a and b have same magnitude

        m^{2}=16

                         m=4,m cannot be negative

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