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  • Provide solution for RD Sharma maths class 12 chapter Scaler and Dot Product exercise 23.2 question 6

Provide solution for RD Sharma maths class 12 chapter Scaler and Dot Product exercise 23.2 question 6

Answers (1)

Answer: \angle A O B=\angle A O D=90^{\circ}

Hint: Prove by 90

Given: P.T diagonal of rhombus are perpendicular bisector each other.

Solution:

ABCD is rhombus in which AB=BC=CD=DA

OA=OC and OB=OD

Now \; in \; \angle B O C \; and \; \angle D O C\\\\ \mathrm{OB}=\mathrm{OD}, \mathrm{BC}=\mathrm{DC} \text { and } \mathrm{OC}=\mathrm{OC}

\begin{aligned} &\angle B O C=\angle D O C \\\\ &\angle B O C+\angle D O C=180^{\circ} \quad \text { (linear pair) } \\\\ &\angle B O C-\angle D O C=90^{\circ} \end{aligned}

Similarly \; \; \angle A O B=\angle A O D=90^{\circ}

Hence the diagonal of rhombus bisect each other at right angle.

 

 

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