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Please Solve R.D.Sharma class 12 Chapter 22 Algbra of Vectors Exercise 22.2 Question 2 Maths textbook Solution.

Answers (1)

Answer:

The possiblilities are

           (i) \vec{a}+\vec{b}+\vec{c}=0

           (ii) \vec{a}=\vec{b}+\vec{c}

           (iii) \vec{c}=\vec{a}+\vec{b}

           (iv) \vec{b}=\vec{a}+\vec{c}

Hint:

Use triangle law of addition.

Given:

\vec{a},\vec{b},\vec{c}  are three sides of triangle                                                                

Solution:                                                                                                                                   

\begin{aligned} &\overrightarrow{A B}=\vec{a} \\ &\overrightarrow{B C}=\vec{b} \\ &\therefore \overrightarrow{A B}+\overrightarrow{B C}=\overrightarrow{A C} \\ &\vec{a}+\vec{b}=-\vec{c} \\ &\vec{a}+\vec{b}+\vec{c}=0 \\ \end{aligned}

The other possibilities are

\begin{aligned} &\vec{a}=\vec{b}+\vec{c} \\ &\vec{c}=\vec{a}+\vec{b} \\ &\vec{b}=\vec{a}+\vec{c} \end{aligned}

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