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Please Solve RD Sharma Class 12 Chapter 22 Algebra of Vectors Exercise 22.6 Question 12 Maths Textbook Solution.

Answers (1)

Answer:

\frac{1}{\sqrt{3}}(\hat{\imath}+\hat{\jmath}+\hat{k})

Hint:

Unit vector  =\frac{P \vec{Q}}{|P \vec{Q}|}

Given:

P and Q are the points  (1,2,3) \text { and }(4,5,6)

Solution:

\begin{aligned} P \vec{Q} &=\vec{Q}-\vec{P} \\ &=(4 \hat{i}+5 \hat{\jmath}+6 \hat{k})-(\hat{\imath}+2 \hat{\jmath}+3 \hat{k}) \\ P \vec{Q} &=((3 \hat{\imath}+3 \hat{\jmath}+3 \hat{k})) \end{aligned}

Any unit vector on the direction of  P \vec{Q} is

\begin{aligned} &\frac{P \vec{Q}}{|P \vec{Q}|}=\frac{3 \hat{\imath}+3 \hat{\jmath}+3 \hat{k}}{\sqrt{3^{2}+3^{2}+3^{2}}}=\frac{(3,3,3)}{\sqrt{27}} \\ &=\frac{3 \hat{\imath}+3 \hat{\jmath}+3 \hat{k}}{3 \sqrt{3}} \\ &=\frac{\hat{\imath}+\hat{\jmath}+\hat{k}}{\sqrt{3}} \end{aligned}

Required unit vector =\frac{1}{\sqrt{3}}(\hat{\imath}+\hat{\jmath}+\hat{k})

Posted by

infoexpert27

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