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Please Solve RD Sharma Class 12 Chapter 4 Algebra of Matrices Exercise Very Short Asnwer Question 64 Maths Textbook Solution.

Answers (1)

Answer: a=\frac{-2}{3} \: and \: b=\frac{3}{2}

Hint: Here we use basic concept of matrix

Given:A= \left [ 0 \: 2b -2\: 3\: 1 \: 3 \: 3a\: 3 -1 \right ] is  symmetric

Solution:

A^{T}=A \: as \: A is symmetric\left [ 0 \: 3 \: 3a\: 2b \: 1\: 3 \: -2\: 3\: -1 \right ]= \left [ 0 \: 2b\: -2\: 3 \: 1\: 3\: 3a\: 3 -1 \right ]

So,

3a=-2\: and\: 2b=3

a=\frac{-2}{3}\; \; \; \; \; b=\frac{3}{2}

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