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Please Solve RD Sharma Class 12 Chapter Algebra of Matrices Exercise 4.2 Question 17 Maths Textbook Solution.

Answers (1)

Answer:\lambda = 2

Hint: Add LHS part of matrix and separate the variable \lambda .Then, solve.

Given:\lambda \begin{bmatrix} 1 & 0 &2 \\ 3 & 4 & 5 \end{bmatrix} +2 \begin{bmatrix} 1 & 2 & 3\\ -1 & -3 & 2 \end{bmatrix} = \begin{bmatrix} 4 & 4 &10 \\ 4 & 2 & 14 \end{bmatrix}

Here, we have to find the value of \lambda

Solution:

\lambda \begin{bmatrix} 1 & 0 &2 \\ 3 & 4 & 5 \end{bmatrix} +2 \begin{bmatrix} 1 & 2 & 3\\ -1 & -3 & 2 \end{bmatrix} = \begin{bmatrix} 4 & 4 &10 \\ 4 & 2 & 14 \end{bmatrix}

\lambda \begin{bmatrix} \lambda & 0 &2\lambda \\ 3\lambda & 4\lambda & 5\lambda \end{bmatrix} +2 \begin{bmatrix} 1 & 2 & 3\\ -1 & -3 & 2 \end{bmatrix} = \begin{bmatrix} 4 & 4 &10 \\ 4 & 2 & 14 \end{bmatrix}

\lambda \begin{bmatrix} \lambda+2 & 0+4 &2\lambda +6 \\ 3\lambda -2 & 4\lambda -6 & 5\lambda +4 \end{bmatrix} = \begin{bmatrix} 4 & 4 &10 \\ 4 & 2 & 14 \end{bmatrix}
Equating this, we get:

\lambda +2 = 4

\lambda = 4 - 2

\Rightarrow \lambda = 2

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