Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • School
  • Please Solve RD Sharma Class 12 Chapter Algebra of Matrices Exercise 4.2 Question 18 Subquestion (i) Maths Textbook Solution.

Please Solve RD Sharma Class 12 Chapter Algebra of Matrices Exercise 4.2 Question 18 Subquestion (i) Maths Textbook Solution.

Answers (1)

best_answer

Answer: X = \begin{bmatrix} -1 & -2\\ -7 & -13 \end{bmatrix}

Hint: Add 2A + B matrix then transpose to RHS.

Given:A = \begin{bmatrix} -1 &2 \\ 3 & 4 \end{bmatrix} , B =\begin{bmatrix} 3 & -2\\ 1 & 5 \end{bmatrix}, 2A + B + x =0
Here, we have to compute X .
Solution:

2A + B + X =0

2\begin{bmatrix} -1 & 2\\ 3 & 4 \end{bmatrix} +\begin{bmatrix} 3 &-2 \\ 1 & 5 \end{bmatrix} + X = \begin{bmatrix} 0 &0 \\ 0& 0 \end{bmatrix}

\begin{bmatrix} -2 & 4\\ 6 & 8 \end{bmatrix} +\begin{bmatrix} 3 &-2 \\ 1 & 5 \end{bmatrix} + X = \begin{bmatrix} 0 &0 \\ 0& 0 \end{bmatrix}

\begin{bmatrix} -2+3 & 4-2\\ 6+1 & 8+5 \end{bmatrix} + X = \begin{bmatrix} 0 &0 \\ 0& 0 \end{bmatrix}

\begin{bmatrix} 1 & 2\\ 7 & 13 \end{bmatrix} + X = \begin{bmatrix} 0 &0 \\ 0& 0 \end{bmatrix}

X = \begin{bmatrix} -1 & -2\\ -7 & -13 \end{bmatrix}

 

Posted by

infoexpert27

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads

Similar Questions

Trending Articles/News

anam-khan

CBSE extends single girl child scholarship registration deadline till November 20
anam-khan

CBSE reminds schools to submit registration data of Class 9, 11 students by October 16

Latest Question