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Provide Solution For  R.D.Sharma Maths Class 12 Chapter 22 Algebra of Vectors  Exercise Very Short Answer Type  Question 24 Maths Textbook Solution.

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Answer: \frac{1}{\sqrt{41}}\left ( 3\hat{i}+4\hat{j}-4\hat{k} \right )

Hint: You must know the rules of vector functions

Given: \vec{a}=\hat{i}+2\hat{j},\vec{b}=\hat{j}+2\hat{k}, find unit vector 3\vec{a}-2\vec{b}

Solution: \vec{a}=\hat{i}+2\hat{j},\vec{b}=\hat{j}+2\hat{k}

Hence,

\begin{aligned} &3 \vec{a}-2 \vec{b}=3(\hat{i}+2 \hat{j})-2(\hat{j}+2 \hat{k}) \\ &=3 \hat{i}+6 \hat{j}-2 \hat{j}-4 \hat{k} \\ &=3 \hat{i}+4 \hat{j}-4 \hat{k} \end{aligned}

Hence, unit vector along,

\begin{aligned} &3 \vec{a}-2 \vec{b}=\frac{3 \hat{i}+4 \hat{j}-4 \hat{k}}{\sqrt{(3)^{2}+(4)^{2}+(-4)^{2}}} \\ &=\frac{3 \hat{i}+4 \hat{j}-4 \hat{k}}{\sqrt{9+16+16}} \\ &=\frac{1}{\sqrt{41}}(3 \hat{i}+4 \hat{j}-4 \hat{k}) \end{aligned}

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