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Provide solution for RD Sharma maths class 12 chapter 22 Algebra of Vectors exercise Fill in the blanks question 22

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Answer:-|\vec{a}|=|\vec{b}|

Hint:-To solve this equation we use rhombus in parallelogram.

Given:-The vector \vec{a}+\vec{b}  bisects the angle between the non-collinear \vec{a} and \vec{b} if ---

Solution:-Non-collinear vector \vec{a} & \vec{b} have found parallelogram ABCD

 A C=\vec{a}+\vec{b}

                                                        

\begin{aligned} &\Rightarrow \angle D A C=\angle C A B=\theta \\\\ &\text { Rhombus } \Rightarrow A B=B C \\\\ &|\vec{a}|=|\vec{b}| \end{aligned}

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