Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • School
  • Explain solution RD sharma class 12 chapter 22 algebra of vectors exercise 22.5, question 12 sub question 3

Explain solution RD sharma class 12 chapter 22 algebra of vectors exercise 22.5, question 12 sub question 3

Answers (1)

The components of \vec{R} along x axis is a vector of magnitude 11 along the negative direction of x axis

The component of \vec{R} along y axis is a vector of magnitude 9 along the negative direction of Y axis

-11\hat{i},-9\hat{j}

Hint: position vector of point (x, y) is given by x\hat{i}+y\hat{j} where \hat{i} and \hat{j} are the unit vector in x and y direction

Given:R=(-11,-9)

Solution:

As we know, position vector of a point (x, y) is given by x\hat{i}+y\hat{j}

So

\vec{R}=-11\hat{i}+(-9)\hat{j}\\ \vec{R}=-11\hat{i}-9\hat{j}\\

The components of \vec{R} along x-axis is a vector of magnitude 11 along the negative direction of x axis

The component of \vec{R} along y-axis is a vector of magnitude 9 along the negative direction of Y axis

Posted by

Info Expert 29

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads

Similar Questions

Trending Articles/News

anam-khan

CBSE results 2024 later for 102 students over fake certificates; board issues show cause notice
anam-khan

What after CBSE Class 12 results 2024? From CUET UG to JEE Advanced, all you need to know
anam-khan

CBSE Results 2024: Maximum full marks scorers in Class 10 mathematics, 12th painting

Latest Question