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Explain solution RD Sharma class 12 chapter 22 Algebra of Vectors exercise Multiple choice question 12 maths

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Answer: \frac{1}{3}(\vec{a}+\vec{b})

Hint: Find the centroid G

Given: Let G is centroid of \Delta A B C \; \; \overrightarrow{A B}=\vec{a}, \overrightarrow{A C}=\vec{b} then bisector \overrightarrow{A G} in terms of \vec{a} \; \&\; \vec{b}

Solution: TakeA as origin them position vector A, B, C are given 0, a  and b respectively

            The centroid =\frac{0+a+b}{3}=\frac{a+b}{3}=\frac{1}{3}(a+b)

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