Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • School
  • Explain solution RD Sharma class 12 Chapter 23 Scalar or Dot Products Exercise Very Short Answer question 7

Explain solution RD Sharma class 12 Chapter 23 Scalar or Dot Products Exercise Very Short Answer question 7

Answers (1)

best_answer

ANSWER:  \overrightarrow{|a|}= |\overrightarrow{b}|

GIVEN:  (\vec{a}+\vec{b}) \cdot(\vec{a}-\vec{b})=0

HINTS:Use the identity of  \left(a^{2}-b^{2}\right)

SOLUTION:

\begin{aligned} &(\vec{a}+\vec{b}) \cdot(\vec{a}-\vec{b})=0 \\ & \end{aligned}

\Rightarrow|\vec{a}|^{2}-|\vec{b}|^{2}=0 \qquad \qquad \qquad\left[\because(a+b)(a-b)=a^{2}-b^{2}\right] \\

\Rightarrow|\vec{a}|^{2}=|\vec{b}|^{2} \\

\Rightarrow|\vec{a}|=|\vec{b}|

Posted by

infoexpert27

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads

Similar Questions

Trending Articles/News

anam-khan

CBSE Class 12 supplementary admit card out; exam on July 28 for over 2.5 lakh
anam-khan

CBSE Class 12 supplementary exams 2026 datesheet out; test on July 28
anam-khan

Centre, CBSE, NCERT defend NEP three-language policy in SC; seek dismissal of pleas against framework

Latest Question