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  • Need Solution for R.D.Sharma Maths Class 12 Chapter 23 Scalar or Dot Products Exercise 23.1 Question 22 Maths Textbook Solution.

Need Solution for R.D.Sharma Maths Class 12 Chapter 23 Scalar or Dot  Products  Exercise 23.1 Question 22 Maths Textbook Solution.

Answers (1)

Answer:  \mid \vec{a\mid }=\mid \vec{b}\mid =1

Hint: You must know the angle of solving vectors.

Given: Find the magnitude of two vectors \vec{a } and \vec{b} that are the same magnitude, are inclined at 60°, whose scalar product is \frac{1}{2} .

Solution: Given that angle between \vec{a } and \vec{b} is 30°

Also,

\mid \vec{a\mid }=\mid \vec{b}\mid

\begin{aligned} &\qquad \vec{a} \cdot \vec{b}=\frac{1}{2}, \ \ \ \ \theta=60^{\circ} \\ \end{aligned}

we Know

\begin{aligned} &\vec{a} \cdot \vec{b}=|\vec{a}||\vec{b}| \cos \theta \\ &\frac{1}{2}=|\vec{a}||\vec{b}| \cos 60^{\circ} \\ &\frac{1}{2}=|\vec{a}|^{2} \frac{1}{2} \\ &|\vec{a}|^{2}=1 \\ &|\vec{a}|=1 \\ &\therefore|\vec{a}|=|\vec{b}|=1 \end{aligned}

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