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  • Need Solution for R.D. Sharma Maths Class 12 Chapter 23 Scalar or Dot Products Exercise 23.1 Question 35 Maths Textbook Solution.

Need Solution for R.D. Sharma Maths Class 12 Chapter 23 Scalar or Dot  Products  Exercise 23.1 Question 35 Maths Textbook Solution.

Answers (1)

Answer:  \sqrt{2\sqrt{3}}=\mid \vec{a}\mid =\mid \vec{b}\mid

Hints: You must know the value of same magnitude incident at an angle of 30°, \vec{a} .\vec{b}=3. Find \mid \vec{a} \mid .\mid \vec{b}\mid

Solution: Given that angle between \vec{a} and \vec{b}  is 30°

Now,

\begin{aligned} &|\vec{a}| \cdot|\vec{b}| \text { and } \vec{a} \cdot \vec{b}=3 \\\\ &\vec{a} \cdot \vec{b}=|\vec{a}||\vec{b}| \cos \theta \\ \end{aligned}

\begin{aligned} &3=|\vec{a}||\vec{a}| \cos 30^{\circ} \\\\ &3=|\vec{a}|^{2}\left(\frac{\sqrt{3}}{2}\right) \\ \end{aligned}

\begin{aligned} &|\vec{a}|^{2}=\frac{6}{\sqrt{3}} \\\\ &|\vec{a}|^{2}=2 \sqrt{3} \\\\ &|\vec{a}|=\sqrt{2 \sqrt{3}} \\\\ &|\vec{b}|=\sqrt{2 \sqrt{3}} \end{aligned}

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