Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • School
  • Need solution for RD sharma maths class 12 chapter 22 Algebra of Vector exercise 22.5 question 10

Need solution for RD sharma maths class 12 chapter 22 Algebra of Vector exercise 22.5 question 10

Answers (1)

best_answer

 

Answer: \frac{1}{2}\hat{i}+\frac{\sqrt{3}}{2}\hat{j}

Hint: a unit vector parallel to

 \vec{a}=\hat{a}=\frac{\vec{a}}{\left | \vec{a} \right |}\\ \left | \vec{a} \right |=\sqrt{x^{2}+y^{2}}

Given: \vec{a}=\hat{i}+\sqrt{3}\hat{j}

Solution:

We can find the magnitude of \vec{a}

\left | \vec{a} \right |=\sqrt{x^{2}+y^{2}}

Here x = 1 and  y=\sqrt{3}

\left |\vec{a} \right |=1^{2}+(\sqrt{3})^{2}\\ =\sqrt{1+3}=4\\ \left |\vec{a} \right |=2

Unit vector parallel to \vec{a}=\hat{a}=\frac{\vec{a}}{\left | \vec{a} \right |}\\

=\frac{1}{2}\left ( \hat{i}+\sqrt{3}\hat{j} \right )\\ =\frac{1}{2}\hat{i}+\frac{\sqrt{3}}{2}\hat{j}

 

Posted by

Info Expert 29

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads

Similar Questions

Trending Articles/News

anam-khan

CBSE Class 12 Maths paper 2025 'moderate but lengthy', questions from PYQ, NCERT
anam-khan

CBSE Board Exam 2025 Live: Class 12 mathematics paper 'moderate but lengthy'; memory-based questions
anam-khan

CBSE Class 12 Chemistry Exam Analysis 2025: Paper 'moderately difficult' but well balanced

Latest Question