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Please Solve R.D.Sharma class 12 Chapter 23 Scaler or Dot Products  Exercise 23.1 Question 30 sub Question 2 Maths Textbook Solution.

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Answer\sqrt{13}

Hint:  You must know the rules of solving vectors.

Given:   \left ( \vec{x}-\vec{a} \right ).\left ( \vec{x}+\vec{a} \right )=12

Solution: Given that  \mid \vec{a}\mid =1 unit vector

                                                        \mid \vec{a}\mid =1

\begin{aligned} &(\vec{x}-\vec{a}) \cdot(\vec{x}+\vec{a})=12 \\ &|\vec{x}|^{2}-|\vec{a}|^{2}=12 \\ &|\vec{x}|^{2}-1^{2}=12 \\ &|\vec{x}|^{2}=13 \\ &|\vec{x}|=\sqrt{13} \end{aligned}

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