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  • Please Solve R.D.Sharma class 12 Chapter 23 Scaler or Dot Products Exercise 23.1 Question 32 Sub Question 2 Maths Textbook Solution.

Please Solve R.D.Sharma class 12 Chapter 23 Scaler or Dot Products  Exercise 23.1 Question 32 Sub Question 2 Maths Textbook Solution.

Answers (1)

Answer:  \sqrt{23}

Hint:  You must know the rules of solving vectors.

Given:   Find \mid \vec{a}-\vec{b}\mid if \mid \vec{a}\mid =3   ,  \mid \vec{b}\mid =4   & \vec{a}.\vec{b}=1

Solution:

\begin{aligned} &|\vec{a}-\vec{b}|^{2}=|\vec{a}|^{2}+|\vec{b}|^{2}-2(\vec{a} \cdot \vec{b}) \\ &|\vec{a}-\vec{b}|^{2}=(3)^{2}+(4)^{2}-2(1) \\ &|\vec{a}-\vec{b}|^{2}=9+16-2 \\ &|\vec{a}-\vec{b}|^{2}=23 \\ &\therefore|\vec{a}-\vec{b}|=\sqrt{23} \end{aligned}

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