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Please solve RD Sharma class 12 chapter 22 Algebra of Vectors exercise Multiple choice question 26 maths textbook solution

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Answer: \overrightarrow{0}

Hint: \overrightarrow{E A}+\overrightarrow{E B}+\overrightarrow{E C}+\overrightarrow{E D}=?

Given:ABCD  is rhombus whose diagonal intersect E then \overrightarrow{E A}+\overrightarrow{E B}+\overrightarrow{E C}+\overrightarrow{E D}  equal

Solution: Since in rhombus diagonal bisects each other, |\overrightarrow{E A}|=|\overrightarrow{E C}| \text { and }|\overrightarrow{E B}|=|\overrightarrow{E D}|

But since they are opposite to each other they are opposite signs

        \begin{aligned} &\overrightarrow{E A}=-\overrightarrow{E C} \\\\ &\overrightarrow{E B}=-\overrightarrow{E D} \\\\ &\overrightarrow{E A}+\overrightarrow{E C}=0 \end{aligned}                ...................(1)

        \begin{aligned} &\overrightarrow{E B}+\overrightarrow{E D}=0 \\ \end{aligned}                ...................(2)

        \overrightarrow{E A}+\overrightarrow{E B}+\overrightarrow{E C}+\overrightarrow{E D}=\overrightarrow{0}

 

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