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Please Solve RD Sharma Class 12 Chapter 4 Algebra of Matrices Exercise Very Short Asnwer Question 43 Maths Textbook Solution.

Answers (1)

Answer: k=17

Hint: Here we use the basic concept of multiplication

Given: \begin{bmatrix} 1 & 2\\ 3& 4 \end{bmatrix}\begin{bmatrix} 3 & 1\\ 2 & 5 \end{bmatrix}=\begin{bmatrix} 7& 11\\ k &23 \end{bmatrix}

Solution:

\begin{bmatrix} 1 & 2\\ 3& 4 \end{bmatrix}\begin{bmatrix} 3 & 1\\ 2 & 5 \end{bmatrix}

=\begin{bmatrix} 1\times 3+2\times2 & 1\times1+2\times5\\ 3\times3+4\times2& 3\times1+4\times5 \end{bmatrix}

=\begin{bmatrix} 3+4 &1+10 \\ 9+8& 3+20 \end{bmatrix}

=\begin{bmatrix} 7 &11 \\ 17& 23 \end{bmatrix}

On Comparing, k=17

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