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  • Please Solve RD Sharma Class 12 Chapter Algebra of Matrices Exercise 4.2 Question 13 Maths Textbook Solution.

Please Solve RD Sharma Class 12 Chapter Algebra of Matrices Exercise 4.2 Question 13 Maths Textbook Solution.

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Answer:

X = \begin{bmatrix} 12 &\frac{4}{3} \\ \\ 4 &\frac{-14}{3} \\ \\ \frac{25}{3} & \frac{28}{3} \end{bmatrix}

Hint: Try to separate the ‘X’ variable into LHS.

Given: A =\begin{bmatrix} 2 &-2 \\ 4 &2 \\ -5 & 1 \end{bmatrix} , B =\begin{bmatrix} 8 & 0\\ 4 & -2\\ 3 & 6 \end{bmatrix} , 2A + 3x = 5B

Here, we have to compute x.

Solution:

2A + 3 X = 5B

2\begin{bmatrix} 2 & -2\\ 4& 2\\ -5& 1 \end{bmatrix}+3X=5\begin{bmatrix} 8 &0 \\ 4& -2\\ 3 & 6 \end{bmatrix}

\begin{bmatrix} 4 & -4\\ 8& 4\\ -10& 2 \end{bmatrix}+3X=\begin{bmatrix} 40 &0 \\ 20& -10\\ 15 & 30 \end{bmatrix}

3X=\begin{bmatrix} 40 &0 \\ 20& -10\\ 15 & 30 \end{bmatrix}-\begin{bmatrix} 4 & -4\\ 8& 4\\ -10& 2 \end{bmatrix}

3X=\begin{bmatrix} 40-4 &0+4 \\ 20-8& -10-4\\ 15+10 & 30-2 \end{bmatrix}

3X=\begin{bmatrix} 36 &4 \\ 12& -14\\ 25 & 28 \end{bmatrix}

X=\frac{1}{3}\begin{bmatrix} 36 &4 \\ 12& -14\\ 25 & 28 \end{bmatrix}

X = \begin{bmatrix} 12 &\frac{4}{3} \\ \\ 4 &\frac{-14}{3} \\ \\ \frac{25}{3} & \frac{28}{3} \end{bmatrix}

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