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Please Solve RD Sharma Class 12 Chapter Algebra of Matrices Exercise 4.2 Question 3 Subquestion (iii) Maths Textbook Solution.

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Answer:  \begin{bmatrix} 2 & -14 &-3 \\ 27 & 11 & -11 \end{bmatrix}
Hint:  Just add and subtract the matrix in the form  2A - 3B + 4C.

Given:   A=\begin{bmatrix} -1 & 0 &2 \\ 3 &1 &4 \end{bmatrix},B=\begin{bmatrix} 0 &-2 &5 \\ 1 & -3 & 1 \end{bmatrix}   and C=\begin{bmatrix} 1 & -5 &2 \\ 6 &0 &-4 \end{bmatrix}

Here, we have to compute 2A - 3B + 4C.
Solution:
2A-3B+4C=2\begin{bmatrix} -1 & 0 &2 \\ 3 &1 &4 \end{bmatrix}-3\begin{bmatrix} 0 &-2 &5 \\ 1 & -3 & 1 \end{bmatrix}+4\begin{bmatrix} 1 & -5 &2 \\ 6 &0 &-4 \end{bmatrix}

                               = \begin{bmatrix} -2 &0 &4 \\ 6 & 2 & 8 \end{bmatrix}-\begin{bmatrix} 0 & -6 &15 \\ 3 &-9 & 3 \end{bmatrix}+\begin{bmatrix} 4 & -20 &8 \\ 24 & 0 & -16 \end{bmatrix}

                                = \begin{bmatrix} -2-0+4 &0+6-20 &4-15+8 \\ 6-3+24 &2+9+0 & 8-3-16 \end{bmatrix}

                                 = \begin{bmatrix} 2 & -14 &-3 \\ 27 & 11 & -11 \end{bmatrix}

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