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  • Provide Solution For R.D. Sharma Maths Class 12 Chapter 23 Scalar or Dot Products Exercise 23.1 Question 14 Maths Textbook Solution.

Provide Solution For  R.D. Sharma Maths Class 12 Chapter 23 Scalar or Dot Products  Exercise 23.1 Question 14 Maths Textbook Solution.

Answers (1)

Answer: proved

Hint: you must know the rules of solving vectors

Given: for any two vectors \vec{a} and \vec{b}

Show: \begin{aligned} &(\vec{a}+\vec{b}) \cdot(\vec{a} - \vec{b})=0 \: \: \: \: \: \: \: \quad \Leftrightarrow|\vec{a}|=|\vec{b}| \\ \end{aligned}

Solution: we have

\begin{aligned} &(\vec{a}+\vec{b}) \cdot(\vec{a} - \vec{b})=0 \: \: \: \: \: \: \: \: \: \quad\left[(a+b)(a-b)=\left(a^{2}-b^{2}\right)\right] \\ &|\vec{a}|^{2}-|\vec{b}|^{2}=0 \\ &|\vec{a}|=|\vec{b}| \end{aligned}

= Proved

Posted by

infoexpert21

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